0=2t^2+2/3t+17

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Solution for 0=2t^2+2/3t+17 equation:



0=2t^2+2/3t+17
We move all terms to the left:
0-(2t^2+2/3t+17)=0
Domain of the equation: 3t+17)!=0
t∈R
We add all the numbers together, and all the variables
-(2t^2+2/3t+17)=0
We get rid of parentheses
-2t^2-2/3t-17=0
We multiply all the terms by the denominator
-2t^2*3t-17*3t-2=0
Wy multiply elements
-6t^3-51t-2=0
We do not support etpression: t^3

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